最近30从www.hoelymoley.com 2023 - 07 - 10 - t12:36:09z //www.hoelymoley.com/feeds/question/11957 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/11957 1 亚设 //www.hoelymoley.com/users/10671 2017 - 07 - 30 - t12:29:09z 2017 - 07 - 30 - t20:21:09z

< p >我的问题担忧的抑郁症锥在承压含水层抽水井:说含水层的透射率是1200 m ^ 2 /天锥将如何改变如果透射率是600 m ^ 2 /天?两种场景中所有含水层参数保持不变,所以是泵送率(比如- 300厘米/小时)。< / p > < p >的主要兴趣是影响半径(没有改变从含水层地区主管)?头部也发生在自我?< / p > < p >谢谢,亚设< / p >

//www.hoelymoley.com/questions/11957/-/11960 # 11960 3 Inkenbrandt //www.hoelymoley.com/users/510 2017 - 07 - 30 - t20:21:09z 2017 - 07 - 30 - t20:21:09z

书< p >基于方程,提高透射率会增加影响半径,降低总压降。压降成正比的泵送率和含水层透射率成反比和存储。< / p > < p > $ $ s = \压裂{Q} {4 t \π}\ int_u ^ \ infty \压裂{e ^ {- y}} y dy $ $ $ $ u = \压裂{r ^{2}年代}{4 tt} $ $ s撤军,r是半径从t, t是透射率,Q是泵送率,和u函数。< / p > < p >应用此方程,可以产生这样的情节:< a href = " https://i.stack.imgur.com/UUajW.jpg " rel = " nofollow noreferrer " > < img src = " https://i.stack.imgur.com/UUajW.jpg " alt = "降落漏斗在0;注意对数尺度" > < / > < a href = " https://i.stack.imgur.com/tsJn5.jpg " rel = " nofollow noreferrer " > < img src = " https://i.stack.imgur.com/tsJn5.jpg " alt = "影响半径的函数T " > < / > < / p > < p >对于这些情节,我用Q = 500, S = 0.01,和T = 4 < / p >

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