冰透雷达“看见”如何通过公里没有被吸收的冰?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换 最近30从www.hoelymoley.com 2023 - 04 - 03 - t20:35:26z //www.hoelymoley.com/feeds/question/13912 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/13912 7 冰透雷达“看见”如何通过公里没有被吸收的冰? uhoh //www.hoelymoley.com/users/6031 2018 - 04 - 15 - t07:34:29z 2019 - 03 - 13 - t05:09:41z < p > BBC新闻文章< a href = " http://www.bbc.com/news/science -环境- 43701375”rel = " noreferrer " >孤立湖泊加拿大冰原底下发现< / >与< em > < / em >开放科学进步的文章< a href = " http://advances.sciencemag.org/content/4/4/eaar4353.full " rel = " noreferrer " >发现冰下湖咸水环境复杂的德文郡冰帽之下,加拿大北极< / >。< / p > < p >这一发现是基于对雷达的“试探”< a href = " https://en.wikipedia.org/wiki/Devon_Ice_Cap " rel = " noreferrer " > < / >在德文郡的冰帽努加拿大。< / p > < p >早期问题< a href = " //www.hoelymoley.com/q/12075/6031 " >什么是可能发生在这些新发现的南极冰层以下的火山?< / >显示地下雷达测量南极冰原,在这种情况下的深度1.5公里,因此总路径长度3公里的冰。< / p > < p >强极性的水分子和与微波辐射吸收和热化。在微波炉这种效应是显而易见的。微波炉可以用来“解冻”冷冻食品甚至几厘米厚,使用权力和长时间减少。这是必要的,因为冷冻水分子吸收低于那些在解冻的领域,但他们仍然完全吸收。< / p > < p >雷达测量穿过公里冰往返,大大超过一块冷冻豌豆的厚度。< / p > < p >冰透雷达如何能够通过这样的长路径长度的冰?有特殊频率这使用,或其他技巧允许极弱反射后批量检测和测量衰减吗? < / p > //www.hoelymoley.com/questions/13912/-/13925 # 13925 6 potatasbravas回答的冰透雷达“看见”如何通过公里没有被吸收的冰? potatasbravas //www.hoelymoley.com/users/12701 2018 - 04 - 16 - t11:44:15z 2018 - 04 - 16 - t11:44:15z < p >水分子与微波相互作用和在微波炉运行在900 mhz - 2.5 ghz。该雷达仪器操作使用非常高的频率在193 mhz无线电波< a href = " https://ieeexplore.ieee.org/stamp/stamp.jsp?arnumber = 5649518 noreferrer“rel = > [1] < / >。< / p > < p >在lower-than-microwave频段,损耗系数要低得多,因此波可以穿透更深的冰盖以最小的吸收。液体水和固体冰之间介电系数的差异是允许他们想象边界和确定冰川下的湖泊从美国宇航局< / p > < p > < a href = " https://www.nasa.gov/content/goddard/airborne-radar-looking-through-thick-ice-during-nasa-polar-campaigns/ " rel = " noreferrer " > [2] < / > < / p > < blockquote > < p >冰,另一方面根据雷达的频率反应不同。它反映了高频无线电波,但尽管是固体,低频雷达可以通过冰在某种程度上。这就是为什么MCoRDS使用频率相对较低,120和240 MHz。这允许仪器探测到冰面,冰和内部层下面的基石。“听起来底部的冰你必须使用频率较低,”约翰·派登说CReSIS科学家。“过高频率和信号将丢失冰。”< / p > < /引用> //www.hoelymoley.com/questions/13912/-/16385 # 16385 5 回答Mingthondraba比尔冰透雷达“看见”如何通过公里没有被吸收的冰? Mingthondraba法案 //www.hoelymoley.com/users/15349 2019 - 03 - 03 - t08:09:45z 2019 - 03 - 03 - t18:00:23z < p >当电磁波通过介质时,它可以与媒介的互动。但这互动取决于介质的电性质。冰,作为电介质,做与事件交互e.m.波传感器。的穿透深度成正比的波长辐射使用(有不同形式的深度可以表达,但最简单的我记得是2.14情商由乔治·约瑟夫遥感的基本原理;< a href = " https://books.google.ca/books?id=peUFLCy4zLYC&printsec=frontcover&source=gbs_atb#v=onepage&q&f=false" rel="nofollow noreferrer">available in Google Book as well):

$l_a=\frac{\lambda_0 \sqrt{\varepsilon'}}{2 \pi \varepsilon''}$

Where $l_a$ is the penetration depth in ice, defined as the depth at wich the signal power falls to $1/e$, $\varepsilon'$ and $\varepsilon''$ are respectively the real and imaginary parts of the dielectric constant, and $\lambda_0$ is the free space wavelength of the electromagnetic radiation.

And so, the microwave radiation (higher wavelength radiations in the electromagnetic spectrum) used in ground penetrating radar can penetrate through the ice surface, the depth thru which it can penetrate being given by the same equation mentioned above. Cheers.

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