如何计算从温度相对湿度,露点,和压力?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换 最近30从www.hoelymoley.com 2023 - 07 - 10 - t01:38:29z //www.hoelymoley.com/feeds/question/16570 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/16570 9 如何计算从温度相对湿度,露点,和压力? ReinstateMonica3167040 //www.hoelymoley.com/users/15513 2019 - 03 - 25 - t00:13:42z 2021 - 02 - 16 - t08:25:42z < p >有一个公式考虑到温度、露点、相对湿度和压力?< / p > < p >我见过一些计算器,如< a href = " http://www.michell.com/us/calculator/ " rel = " noreferrer " > < / >,但我想知道如何计算这个自己。< / p > < p >我知道有几个公式可以计算这个温度和露点,但自从我写一个程序,我希望能够使用的压力数据,我有更大的准确性。< / p > //www.hoelymoley.com/questions/16570/-/16575 # 16575 9 Camilo Rada回答的如何计算从温度相对湿度,露点,和压力? 卡米洛·Rada //www.hoelymoley.com/users/11908 2019 - 03 - 25 - t02:31:34z 2021 - 02 - 16 - t08:25:42z < p >您可以参考< a href = " //www.hoelymoley.com/q/14899/11908 " > < / >这个问题的更多细节的起源这个公式(基于< a href = " https://en.wikipedia.org/wiki/Dew_point " rel = " nofollow noreferrer " > Magnus近似< / >),但如果你做一些代数表达式有露点(<跨类= " math-container " > TD < / span >美元)作为温度的函数(类< span = " math-container " > T < / span >美元)和相对湿度(<跨类= " math-container " > RH < / span >)美元,你得到< / p > < p > <跨类= " math-container " > RH = 100美元\,e ^{\ \大左(\压裂{c \ b (TD-T)} {(c + T) (c + TD)} \右)}$ < / span > < / p > < p >与< span class = " math-container " > b = 17.625美元< / span >和<跨类= " math-container " > c = 243.04 < / span >美元。< / p > < p >在这种情况下,在< span class = " math-container " > TD < / span >美元是你的一个输入变量,不需要考虑的压力,压力没有影响类< span = " math-container " > RH < / span >美元,或者更确切地说,压力依赖已经被认为是通过< span class = " math-container " > TD < / span >美元。压力将发挥作用,如果你计算类< span = " math-container " > TD < / span >美元从水蒸气压力,因为水蒸气压力就是< a href = " https://en.wikipedia.org/wiki/Relative_humidity # Pressure_dependence”rel = " nofollow noreferrer " > < / >小依赖在大气压力。

The Magnus approximation above is considered valid for:

$0^oC < T < 60^oC$
$1\% < RH < 100\%$
$0^oC < TD < 50^oC$

There are also other equivalent formulas that extends their validity range by changing the constants, like this one

$RH=100\cdot10^{\Large m\left( \frac{TD}{TD+T_n}-\frac{T}{T+T_n}\right)}$

Where values for the constants $m$ and $T_n$ depend on temperature and are tabulated:

enter image description here

See this document for more details.

There are also very simple approximations to these formulas, like

$RH \approx 100 - 5 (T-TD)$

You can find a discussion on the accuracy of this approximation here.

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