剪切变形的符号问题条款——地球科学堆栈交换江南电子竞技平台江南体育网页版 最近30从www.hoelymoley.com 2023 - 07 - 10 - t12:26:26z //www.hoelymoley.com/feeds/question/18003 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/18003 1 关于剪切变形的迹象 Lyndz //www.hoelymoley.com/users/16927 2019 - 09 - 16 - t07:27:08z 2021 - 09 - 18 - t17:31:55z < p >我有以下方程的剪切变形区域的气象。引用< a href = " http://www.zamg.ac.at/docu/Manual/SatManu/main.htm?/docu/Manual/SatManu/CMs/Def/backgr.htm " rel = " nofollow noreferrer " > < / >。< / p > < p >剪切= <跨类= " math-container " > $ \ \压裂压裂{dV} {dx} + {dU} {dy} $ < / span > < / p > < p > <跨类= " math-container " > ${你}$ < / span >和<跨类= " math-container " > {V} < / span >美元的纬向和经向风,分别;< span class = " math-container " > $ {x} $ < / span >和<跨类= " math-container " > $ {y} $ < / span >经度和纬度,分别。

I would like to know what does it mean to have if:

a) $\frac{dV}{dx}$ < 0 and $\frac{dU}{dy}$ > 0;

b) $\frac{dU}{dy}$ < 0 and $\frac{dV}{dx}$ > 0;

c) both $\frac{dV}{dy}$ and $\frac{dU}{dx}$ are less than 0;

d) both $\frac{dV}{dy}$ and $\frac{dV}{dx}$ are greater than 0.

//www.hoelymoley.com/questions/18003/-/18047 # 18047 3 由AtmosphericPrisonEscape回答问题的符号剪切变形的条件 AtmosphericPrisonEscape //www.hoelymoley.com/users/489 2019 - 09 - 22 - t02:10:31z 2019 - 09 - 22 - t02:10:31z < p >你尝试素描的情况吗?尝试一个正方形网格,定义x和y,然后把< span class = " math-container " > U < / span >和美元<跨类= " math-container " > V < / span >组件到美元的一个网格点,你选择为起点。

Now proceed to implement a). For example, from your starting arrows, go to the next grid point eastwards, and implement $\frac{dV}{dx}<0$, i.e. the upwards pointing arrows become smaller as you go eastwards. Do the same for U. Repeat for enough grid points until you see a pattern. Now connect $U$ and $V$ components into the final, two-dimensional velocity vector $\vec v$.

In this way you will possibly self-answer your question. I don't know if I can help you more, because I don't know what you mean with \

I would like to know what does it mean to have

The end result will be the graphical representation of a vector field. The shear tensor simply measure the amount of shear in each vector field. You will discover that some field structures surprisingly possess shear, while others don't.

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