相对湿度是如何从干湿球读数确定?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换 最近30从www.hoelymoley.com 2023 - 07 - 10 - t13:15:18z //www.hoelymoley.com/feeds/question/19151 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/19151 6 相对湿度是如何从干湿球读数确定? uhoh //www.hoelymoley.com/users/6031 2020 - 02年- 08 - t01:07:43z 2021 - 07 - 19 - t10:36:45z < p > < a href = " //www.hoelymoley.com/q/19145/6031 " >的问题什么是第二个温度计在图像从埃斯佩兰萨南极温度记录吗?< / >显示了可能是一个湿/干球的设置。< / p > < p >我给一个朋友来测量湿度的乐趣(这是我认为很有趣)。我会了解他们在无数年前地球科学类,所以当我碰巧看到一江南体育网页版个最近我抓住了这个机会。< / p > < p >我理解的基础,如何显示湿度;干燥空气,水会蒸发越快,温度越低,湿球将关于干球。< / p > < p >得到湿度数值设置你使用粗表在前面(表的背面有一个更好的盒子)查找干球温度和干-湿差找到一个近似的湿度。例如,如果我抬头分别为19岁和2°C的(大概是什么图像所示)我得到相对湿度约81%。< / p > < p >但假设我把相机覆盆子π和成像两个温度计,处理图像并确定这两个温度和想没有插值计算相对湿度表。< / p > < p > <强>问题:< /强>相对湿度是如何从干湿球读数确定?哪些步骤,是一个很好的来源所涉及的方程和参数?< / p > < p > < em >点击全尺寸< / em > < / p > < p > < a href = " https://i.stack.imgur.com/Yu941.jpg " rel = " noreferrer " > < img src = " https://i.stack.imgur.com/Yu941l.jpg " alt = "湿/干球”设置测量相对湿度> < / > < / p > //www.hoelymoley.com/questions/19151/-/19153 # 19153 6 弗雷德回答的相对湿度是如何从干湿球读数确定? 弗雷德 //www.hoelymoley.com/users/2470 2020 - 02年- 08 - t04:36:41z 2021 - 04 - 30 - t18:08:13z < p > < em >编辑:2021年5月1日< / em > < / p > < p >下列程序使用不正确的方法从455页开始从书的扫描部分如下图所示,从原来的答案。< / p > < p >的过程是一个多级的过程适合电子表格或编程代码。< / p > < p >方程使用国际标准单位。< / p > < p > < em > <强> 1。的饱和蒸汽压计算干球温度< /强> < / em > < / p > < p >这是使用方程:< span class = " math-container " > $ p " _ {ws} \ e = \ 0.61078 \ \ ^ {17.27 T_{干}/识别(273.3 + T_{干})识别}\ \ kPa $ < / span > < / p > < p >, < span class = " math-container " > T_{干}识别< / span >美元是干球温度。< / p > < p > < em > <强> 2。计算饱和蒸汽压在湿球温度< /强> < / em > < / p > < p >这是使用方程:< span class = " math-container " > $ p ' _ {ws} \ e = \ 0.61078 \ \ ^ {17.27 T_{湿}/识别(273.3 + T_{湿})识别}\ \ kPa $ < / span > < / p > < p >, < span class = " math-container " > T_{湿}识别< / span >美元湿球温度。< / p > < p > < em > <强> 3。计算水分饱和空气的湿球温度< /强> < / em > < / p > < p >使用方程:< span class = " math-container " > r_o \ = \ \压裂{18.016 \美元(1.0048)28.9664 p ' _ {ws}} {\ (P_ {atm} -1.0048) p ' _ {ws}} \ \公斤/公斤$ < / span > < / p > < p >, < span class = " math-container " >美元P_ {atm} $ < / span >大气压力< / p > < p > < em > <强> 4。水蒸气压力的计算焓湿球温度< /强> < / em > < / p > < p > <跨类= " math-container " > $ H ' _{我们}\ = \ -0.00000662 \ t_{湿}识别^ 3 - 0.000194 \ t_{湿}^ 2 + 1.8375识别\ t_{湿}识别+ 2500.83 \ \焦每公斤$ < / span > < / p > < p > < em > <强> 5。计算焓液态水的湿球温度< /强> < / em > < / p > < p > <跨类= " math-container " > $ H ' _{王}\ = \ 0.0000063 \ t_{湿}识别^ 3 - 0.000727 \ t_{湿}^ 2 + 4.2058识别\ t_{湿}识别+ 0.03 \ \焦每公斤$ < / span > < / p > < p > < em > <强> 6。计算焓水蒸气压力的干球温度< /强> < / em > < / p > < p > <跨类= " math-container " > $ H ' _ {wi} \ = \ -0.00000662 \ t_{干}识别^ 3 - 0.000194 \ t_{干}^ 2 + 1.8375识别\ t_{干}识别+ 2500.83 \ \焦每公斤$ < / span > < / p > < p > < em > <强> 7。计算水分饱和空气的湿球温度< /强> < / em > < / p > < p > <跨类= " math-container " > $ r \ = \ \压裂{r_o * (H ' _{我们}- H ' _{王})- (1.005 \ t_{干}识别-1.005 \ t_{湿})识别}{(H ' _ {wi} - H ' _{王})}\ \公斤/公斤$ < / span > < / p > < p > < em > <强> 8。计算蒸汽压< /强> < / em > < / p > < p > <跨类= " math-container " > $ P_w \ = \ \压裂{r \ P_ {atm}} {1.0048 \ (18.016/28.9664 + r)} \ \ kPa $ < / span > < / p > < p > < em > <强> 9。计算相对湿度< /强> < / em > < / p > < p > <跨类= " math-container " > $ \ \ = \ P_wφ/ p”_ {ws} $ < / span > < / p > <人力资源/ > < p > < em > <强>之前的回答——相关页的扫描从参考书< /强> < / em > < / p > < p >我要老学校。< / p > < p >以下图片中的相关页面:< em >环境工程在南非矿山< / em >,南非的矿井通风的社会,1989年,页451 - 455。 They give the psychometric equations that are required to calculate relative humidity from wet & dry bulb temperatures.

enter image description here

enter image description here

enter image description here

enter image description here

enter image description here

For simplicity, I use the less accurate equations on p455, section 9.2.

As a slight diversion, the other way to measure wet & dry bulb temperatures is to use a whirling hygrometer. The wet bulb temperature is always read first because it will start to warm as soon as the hygrometer stops whirling.

enter image description here

Baidu
map