如何计算gps定位根据方向和距离吗?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换 最近30从www.hoelymoley.com 2023 - 07 - 10 - t05:55:24z //www.hoelymoley.com/feeds/question/19402 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/19402 2 如何计算gps定位根据方向和距离吗? 唐布兰森 //www.hoelymoley.com/users/13510 2020 - 03 - 07 - t22:36:12z 2020 - 03 - 08 - t18:19:11z < p >我需要计算一个点的gps坐标“北52°西2.67连锁”从一个已知的位置。让这个计算过程是什么?如果可能的话,从37 n - 91 w。< / p >

There's an answer to this on Mathematics on a plane. That answer, plus knowing degrees/meter around my location will provide a sufficiently accurate answer for the short distances in my case. Given that, this question is probably a good candidate to be closed.

//www.hoelymoley.com/questions/19402/-/19406 # 19406 4 父亲的回答如何计算gps定位根据方向和距离吗? 父亲 //www.hoelymoley.com/users/6550 2020 - 03 - 08 - t17:35:35z 2020 - 03 - 08 - t18:19:11z < p >答案在飞机上你提供的链接工作,而在一个球体,你想测量很小的距离与地球的半径和距离最近的杆,和2.67链是微小的。< / p > < p >剩下的答案我会假设地球是一个球体,这很准确,除非你需要伟大的准确性——也就是说,几乎任何除了测量足够准确。< / p > < p >第一步是将你的距离和方向以东和以北距离——答案告诉有关。< / p > < p >第二步是将这两个距离转换成度的纬度和经度,纬度,你只需要知道一个学位措施类< span = " math-container " >美元R_地球{}\ cdot \压裂{\π}{180}< / span >美元和学位经度措施类< span = " math-container " >美元R_地球{}\ cdot \压裂{\π}{180}\ cdot cos(纬度)< / span >美元。< / p > < p >作为最后一步,你只需要这些角度和位置的纬度和经度。< / p > < p >与您的数据:< / p > < pre > <代码>比;#地球半径链比;(r & lt; - 3958.8 * 80)[1] 316704比;比;#轴承,纬度和经度弧度比;(br & lt; - -52/180 *π)[1]-0.907571211比;(latr & lt; - 37/180 *π)[1]0.6457718232比;(lonr & lt; - -91/180 *π)[1]-1.588249619比;比; #1 Distance to North and East in chains > (east <- sin(br)*2.67) [1] -2.103988712 > (north <- cos(br)*2.67) [1] 1.643816139 > > #One degree in chains > (deglat <- r*pi/180) [1] 5527.527554 > (deglon <- r*pi/180*cos(latr)) [1] 4414.479788 > > #2 distance in degrees > (dlat <- north/deglat) [1] 0.0002973872356 > (dlon <- east/deglon) [1] -0.000476610793 > > #3 arriving point (GPS coordinates) > (lat <- 37+dlat) [1] 37.00029739 > (lon <- -91+dlon) [1] -91.00047661
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