< p >我要计算总类< span = " math-container " > $ \ rm {NO_2} $ < / span >数量在一年内使用卫星< a href = " https://developers.google.com/earth-engine/datasets/catalog/COPERNICUS_S5P_OFFL_L3_NO2 " rel = " nofollow noreferrer " > < / > Sentinel-5p NO2数据集。但问题是哨兵卫星数据存储在<跨类= " math-container " > \ rm \美元压裂{摩尔}{m ^ 2} $ < / span >单位。但是我必须把它比作<代码>磅< /代码>或<代码>吨> < /代码或任何其他单位比较<跨类= " math-container " > $ \ rm {NO_2} $ < / span >数量与地面<跨类= " math-container " > $ \ rm {NO_2} $ < / span >测量。< / p > < blockquote > < p > <强>例子:< /强>在我们的卫星数据集,我们<强>对流层<跨类= " math-container " > $ \ rm {NO_2} $ < / span >列数密度< / >强的单位是美元<跨类=“math-container”> \ rm \压裂{摩尔}{m ^ 2} $ < / span >。我们要计算总年度<跨类= " math-container " > $ \ rm {NO_2} $ < / span >加州。今年我们有总结所有加州的数据。然后我们得到一个总年度<跨类= " math-container " > $ \ rm {NO_2} $ < / span > 4200 <跨类= " math-container " > \ rm \压裂{摩尔}{m ^ 2} $ < / span >。我想把这<代码>克< /代码>或<代码>吨< /代码>或<代码>磅> < /代码。例如,每年总类< span = " math-container " > $ \ rm {NO_2} $ < / span >加州是35000吨。< / p > Also, if I convert that $\rm\frac{mol}{m^2}$ to $\rm\frac{molec}{cm^2}$, is it then possible to convert it to total gram
or ton
?
Research: I have asked that question in here. After getting answers, I thought I have found the solutions. But after some more research, it turns out not easy. Because in satellite data what we get is tropospheric vertical column number density and convert them to total mass like total $\rm{NO_2}$ in gram or ton is not straightforward. These forum posts (#1, #2, #3) also somewhat similar to mine, but I didn't get quite a solution to my problem.
EDIT: I know that we can easily multiply by area in $\rm m^2$ to cancel out $\rm m^2$ in the unit and multiple by $\rm{NO_2}$ molar mass, but this is not a ground-based problem. We are talking about satellite imagery dataset especially tropospheric vertical column density. #1, #2, #3 These posts shows why it is different for converting satellite imagery units to ground-based units.