为什么相对湿度下降如果冬天我打开窗户吗?温度下降呢?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换 最近30从www.hoelymoley.com 2023 - 07 - 07 - t00:33:15z //www.hoelymoley.com/feeds/question/20902 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/20902 3 为什么相对湿度下降如果冬天我打开窗户吗?温度下降呢? user250614 //www.hoelymoley.com/users/21933 2021 - 02年- 26 - t11:19:57z 2021 - 04 - 01 - t18:56:03z < p >我明白40% rel.嗡嗡声。在0°C是绝对湿度低于40%,20°C。然而,假设我们有2类< span = " math-container " > ~ m ^ 3美元< / span >的空气。都是40%的潮湿在20°C。现在我们交换1 < span class = " math-container”> ~ m ^ 3美元< / span > 40%潮湿的空气在0°C。然后根据< a href = " https://wiki.unece.org/download/attachments/23101992/image2014 - 5 - 19% - 2010% - 3 - a38%3a41.png?version=1& modificationDate = 1400488842518, api = v2”rel = " nofollow noreferrer " > < / >这张照片我们应该得到7美元<跨类= " math-container " > ~ g \, m ^ {3} < / span >美元和2类< span = " math-container " > ~ g \美元,m ^ {3} $ < / span >每一部分的绝对湿度。这是4.5 < span class = " math-container”> ~ g \美元,m ^ {3} < / span >平均美元。现在温度应该10°C (?)。然后,4.5 < span class = " math-container”> ~ g \美元,m ^ {3} < / span >意味着美元相对湿度50%左右的!那么为什么现实相对湿度下降呢? Is it because the temperature would actually be higher somehow?

 //www.hoelymoley.com/questions/20902/-/20917 # 20917 4 由User123回答为什么相对湿度下降如果冬天我打开窗户吗?温度下降呢? User123 //www.hoelymoley.com/users/19122 2021 - 02年- 27 - t11:33:04z 2021 - 04 - 01 - t18:56:03z < p >让我们做这个准确的方程。我们知道如何计算温度的饱和水蒸气压力<跨类= " math-container " > $ T $ < / span >: < / p > < p > <跨类= " math-container " > $ $ e_s (T) = e_ {s0} e ^{\压裂{h_i} {R_w}(\压裂{1}{T_ {s0}}识别- \压裂{1}{T})} = 610 \文本{Pa} \乘以e ^{5423(\压裂{1}{273 \文本{K}} - \压裂{1}{T})} $ $ < / span > < / p > < p > <跨类= " math-container " > e_s < / span >是美元饱和水蒸气压力的函数< span class = " math-container " > T < / span >美元在帕斯卡< br / > <跨类= " math-container " > T < / span >美元是开尔文温度< / p > < p >所以,饱和水蒸气压力<跨类= " math-container " > T = 0°C = 273 K美元< / span > = < span class = " math-container " >美元e_s Pa 610 (273 K) = < / span >。同样,< span class = " math-container " >美元e_s pa 2360 (293 k) = < / span >和<跨类= " math-container " >美元e_s pa 1230 (283 k) = < / span >。< / p > < p >所以我们有两个包裹空气:1。20°C, 40%和2。0°C, 40%。什么是水蒸气的质量在两个包裹吗?< span class = " math-container " > $ $ e = f \ * e_s (T) $ $ < / span > <跨类= " math-container " > f < / span >是美元相对湿度,< span class = " math-container " > e < / span >是美元水蒸气压力< / p > < p > <跨类= " math-container " > $ $ m (T) = \压裂{电动车}{R_w T} = \压裂{f \ * e_s V (T) \ *} {R_w \ * T} = \压裂{fe_s V (T)}{461 \压裂{J}{公斤}T} $ $ < / span > < / p > < p > <跨类= " math-container " > $ $ m (293 k) = 0.0070公斤$ $ < / span > <跨类= " math-container " > $ $ m (273 k) = 0.0019公斤$ $ < / span > < / p > < p >下一步是把这两个质量:< / p > < p > <跨类= " math-container " > $ $ m = m (293 k) + m (273 k) = 0.0089公斤$ $ < / span > < / p > < p >密度是<跨类= " math-container " > $ \ρ= \压裂{m} {V} = 0.0045 \压裂{公斤}{m ^ 3} $ < / span > < / p > < p >的水蒸汽压力:< span class = " math-container " > $ $ e = \ρRT = 587 pa $ $ < / span >相对湿度:< span class = " math-container " > $ $ f = \压裂{e} {e_s (283 k)} = 0.477 $ $ < / span > < / p > < p >这是大约48%的相对湿度。< / p > < p >为什么我把这里这么多方程?简单!这些方程保持高度的准确性,所以他们不能是错误的。为什么相对湿度下降的现实呢?

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