如何计算温室气体辐射?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换 最近30从www.hoelymoley.com 2023 - 07 - 07 - t12:00:33z //www.hoelymoley.com/feeds/question/22768 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/22768 5 如何计算温室气体辐射? import_hill //www.hoelymoley.com/users/24381 2021 - 09 - 05 - t12:37:45z 2021 - 09 - 25 - t08:58:32z < p > < a href = " https://i.stack.imgur.com/FTZm4.jpg " rel = " noreferrer " > < img src = " https://i.stack.imgur.com/FTZm4.jpg " alt = "在这里输入图像描述" / > < / > < / p > < p >如何将计算后的值辐射(324在这个图中)如果没有提供。

According to this website, it is "equivalent to 100 percent of the incoming solar energy" but from this diagram, that statement appears to be false as the incoming solar energy is 342 while the back radiation is 324.

Could someone tell me how to do it? Or is it just not possible?

//www.hoelymoley.com/questions/22768/-/22873 # 22873 1 帕特的回答如何计算从温室气体辐射吗? 帕特 //www.hoelymoley.com/users/24481 2021 - 09 - 24 - t10:32:46z 2021 - 09 - 25 - t08:58:32z < p >背面辐射似乎求和计算大气辐射所有组件(包括云)吸收,然后向上减去它发出的辐射。剩下的就是它发出的辐射向下(即辐射)。In the figure it is indeed: $$ (67\ \mathrm{Wm^{-2}} + 24\ \mathrm{Wm^{-2}} + 78\ \mathrm{Wm^{-2}} + 350\ \mathrm{Wm^{-2}}) - (165\ \mathrm{Wm^{-2}} + 30\ \mathrm{Wm^{-2}}) = 324\ \mathrm{Wm^{-2}}$$

The "equivalent to 100 percent of the incoming solar energy" reference in NASA's website is a rough approximation and it is not a result of some conservation law that says the two amounts must be exactly equal. It only means "we have estimated that the atmosphere's back radiation is approximately equal to the incoming solar radiation" (and indeed $324\ \mathrm{Wm^{-2}}$ is approximately 100 percent of $342\ \mathrm{Wm^{-2}}$). Other similar estimations are suggesting slightly different amounts and percentages, but all are more or less quite close to each other for each radiation component. See for example the respective figure in Chapter 2 of 2013 IPCC Report:

IPCC 2013, The Physical Science Basis, Chapter 2, Figure 2.11

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