最近30从www.hoelymoley.com 2023 - 07 - 10 - t01:41:53z //www.hoelymoley.com/feeds/question/25060 https://creativecommons.org/licenses/by-sa/4.0/rdf //www.hoelymoley.com/q/25060 4 埃里克·埃里克森 //www.hoelymoley.com/users/28735 2023 - 03 - 24 - t14:17:25z 2023 - 03 - 25 - t01:54:58z

< p >我不知道其他的帖子。< / p > < p >我在读B.M. Das的岩土工程教科书,第六版。< / p > < p > 3.1问题如下:< / p > < p >对于给定的土壤,表明< span class = " math-container " > $ $ e = \压裂{\ gamma_{坐在}- \ gamma_w} {\ gamma_d - \ gamma_{坐在}+ \ gamma_w} $ $ < / span > < / p > < p > <跨类= " math-container " > $ e = \压裂{V_v} {V_s} $ < / span >, < span class = " math-container " > V_v < / span >美元是我特定的土壤孔隙的体积和<跨类= " math-container " > V_s美元< / span >是固体材料的体积。< / p > < p > <跨类= " math-container " > \美元gamma_{坐在}$ < / span > <跨类= " math-container " > \ gamma_d美元< / span > <跨类= " math-container " > \ gamma_w < / span >美元是饱和土壤的容重(所有孔隙水),干土(无水)和水在<跨类= " math-container " > kN / m ^ 3美元< / span > < / p > < p >我的尝试:< span class = " math-container " > W_s美元,美元W_w < / span >是固体的重量和体重的水饱和的样本。总量是< span class = " math-container”>美元V_{合计}= V_s + V_v = 1 $ < / span > < / p > < p > <跨类= " math-container " > $ $ e = \压裂{\ gamma_{坐在}- \ gamma_w} {\ gamma_d - \ gamma_{坐在}+ \ gamma_w} = \压裂{\压裂{W_s + W_w} {V_{合计}}- \压裂{W_w} {V_v}}{\压裂{W_s-W_s-W_w} {V_{合计}}+ \压裂{W_w} {V_v}} = \压裂{V_v (W_s + W_w) -W_w} {W_w - V_vW_w} = \压裂{V_vW_s + W_w (V_v-1)} {W_wV_s} = e * \压裂{W_s} {W_w} 1 $ $ < / span > < / p > < p >我不能找到一种方法除此之外,是错误的。我们可以移动变量类< span = " math-container " > $ e = \压裂{V_vW_s} {V_sW_w} 1 = \压裂{\ gamma_s} {\ gamma_w} 1 = G_s-1 $ < / span >, < span class = " math-container " > G_s < / span >美元被定义为固体材料的比重和不变不管孔隙比(<跨类= " math-container " > e < / span >)美元。因此< span class = " math-container " > e = G_s-1 < / span >美元必须是错的,因为< span class = " math-container " > e < / span >美元应该是变量与恒定土壤类< span = " math-container " > G_s美元< / span > < / p >

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