这将是对潮汐的影响如果地球没有倾斜?- 江南体育网页版- - - - -地球科学堆江南电子竞技平台栈交换

这将是对潮汐的影响如果地球没有倾斜?

2016 - 08 - 28 - t04:54:39z

我想知道是什么影响/对潮汐的影响如果地球没有倾斜(垂直于黄道面)?

user2821回答的是什么对潮汐的影响如果地球没有倾斜?

2016 - 08 - 29 - t09:33:22z

我不回答假设性的问题,但可能会影响潮汐倾斜,已经有一些研究的话题。希望他们能激发进一步的想法和猜测。看来,报告的主要结果为你应该了解月球,太阳和地球控制潮流以及< a href = " https://en.wikipedia.org/wiki/Tidal_force " rel = " nofollow noreferrer " > < / >潮汐力的作品。 < a href = " https://i.stack.imgur.com/NiwZD.png " rel = " nofollow noreferrer " > < img src = " https://i.stack.imgur.com/NiwZD.png " alt = "拉斯卡尔1986创意共同维基媒体”> < / > 轴倾角的变化随着时间的推移,从拉斯卡尔(1986) 我们不能完全消除倾斜,但我们可以看看恒轴倾角的变化< a href = " https://en.wikipedia.org/wiki/Milankovitch_cycles " rel = " nofollow noreferrer " >米兰科维奇旋回< / >。一些人认为这2.4°变化的影响相当大。< a href = " http://clivebest.com/blog/?p = 7300 " rel = " nofollow noreferrer " >克莱夫最好的博客< / >为主要参数,提出一些好的参考。参见< a href = " https://wattsupwiththat.com/2014/01/14/do-super-tides-kick-start-interglacials/ " rel = " nofollow noreferrer " >讨论< / >和< a href = " http://www.pnas.org/content/97/8/3814.abstract " rel = " nofollow noreferrer " > < / >潮汐变化和冰川作用。 然而,很难指定有多少的影响直接相关的倾斜变化、海平面变化和冰川作用也影响与潮汐交互模式。 < a href = " https://i.stack.imgur.com/EiZ9e.png " rel = " nofollow noreferrer " > < img src = " https://i.stack.imgur.com/EiZ9e.png " alt = "图从Wilmes和绿色2014 " > < / > 这个模型从Wilmes和绿色(2014)表明,更高的潮汐在LGM高纬度地区,21.000年前。模型是基于海平面变化和冰川作用。

From the astronomical data, it however does appear that the impact (tractional acceleration) of the Moon was much higher at large latitudes when the obliquity of the tilt is large (see figure) and this resulted in higher tides at latitudes where glaciation forms.

With less or no tilt, tides at large latitudes should be even smaller and maybe contribute to less breakup of ice sheets.

arkaia回答的是什么对潮汐的影响如果地球没有倾斜?

2016 - 08 - 29 - t15:55:34z

一个简单的方法来估计的影响是简化问题。如果地球的轨道,太阳和月亮是圆形的和在同一个平面上,和地球没有倾斜,仅存的潮汐选民将M_2和S_2美元美元(倍潮和结合潮汐:M_4,美元MS_4美元…)。其余的潮汐成分可以表示为线性组合的利率变化的基于剩余的营力:< a href = " https://en.wikipedia.org/wiki/Orbital_eccentricity " rel = " nofollow noreferrer " >轨道偏心率< / >和< a href = " https://en.wikipedia.org/wiki/Orbital_inclination " rel = " nofollow noreferrer " >倾向< / >和< a href = " https://en.wikipedia.org/wiki/Axial_tilt " rel = " nofollow noreferrer " >轴倾角< / >。 的调制主成分波的振幅A_M美元,美元\ eta_M = A_M cos (\ omega_M t)美元,振幅A_c美元的另一个组成部分是:$ \ eta_t = (A_M + A_ccos (\ omega_c t)因为(\ omega_Mt)美元。表示这是一个线性组合的利率变化给$ \ eta_t = A_Mcos (\ omega_Mt) + {A_c \ over2} cos (\ omega_M - \ omega_c) t + {A_c \ over2} cos (\ \ omega_c omega_M +) t $,这样原始的振幅保持不变,而两个额外的组件稍微不同的频率出现。 在轴倾角的影响的情况下,根据太阳能参数调节的主要频率(月球轨道的倾角不受轴向倾斜的影响)。太阳赤纬的周期是一个恒星年(365.2564天)。In the case of the modulation of the $M_2$, the resulting periodicities are 1 cycle/solar day ± 1 cycle/sidereal year. The two resulting constituents are $P_1$ and $K_1$. $P_1$ is known as the solar declinational diurnal constituent. The case of $K_1$ is slightly more complex as the inclination of the Moon also results in a contribution at this frequency. The rest of the tidal constituents are also modified accordingly, but their amplitudes are much smaller.

In short, the removal of the axial tilt will result in the removal of the $P_1$ tidal constituent (and some other minor ones) and an amplitude decrease in the $K_1$ constituent.

$K_1$ amplitude and phase from AVISO. The maximum $K_1$ amplitudes of around 0.4m are found south of Alaska and west of the Kamchatka Peninsula in the Sea of Okhotsk. The amplitude of the $P_1$ constituent is about half of $K_1$ with a maximum of around 0.2m in the Sea of Okhotsk. Overall, the effect of the tilt on tides is pretty minor relative to the rest of the effects.