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如何计算w-wind吗?

我的模型(AGCM)不计算w-wind(风速的垂直分量)。然而,我确实有以下可用变量从AGCM输出:

除,v-wind位势、欧米茄和一些其他变量(如温度、含湿量)23压力水平。

除和v-wind风速的水平分量,重力势是地球引力的潜力,ω是解决吗ω方程。

我想计算通过使用除w-wind v-wind位势ω。所建议的JeopardyTempest下面的回答,我可以计算w-wind使用方程w =−ω/ρg。这是多么可靠的如果我不使用w =−ωRT / pg吗?

回答

ω,ω是气象学w密切相关。它可以使用链式走向w([这提醒][1]从沃特金斯SJSU帮助)……ω= dp / dt = (dp / dz) (dz / dt) = (dp / dz) w <一口> * [p是压力,t是时间,z是高度,和w身高垂直运动坐标)* < /一口>通常一般气象可以估计dp / dz使用(静压近似)[2],大概认为重力和浮力平衡。这使得方程:dp / dz =−ρg <一口> *(ρ是空气密度和g是重力加速度)* < /一口>所以意味着你可以继续ω= (dp / dz) w =−ρgw导致* * w =−ω/ρg * *。* *请注意,这并不总是有效的。* *,(霍尔顿的介绍动力气象学,卷1][3][第20页][4]表明:>这个条件的流体静力平衡提供了一个极好的>近似垂直依赖>中的压力场的气氛。只有强烈的小规模系统如暴风>线条和龙卷风有必要考虑偏离>流体静力平衡。这是一个松散的主意。已经有一段时间,但基本上我记住它,静水强烈时有效的垂直加速度(因此垂直运动时在地表附近)相比,规模要小得多的水平运动/加速度。所以实际上,这不是真正的龙卷风和对流。 So you get very correct values for strong thunderstorms. But it will help you diagnose regions of rising motion. You can look a bit more towards breaking it down into more advanced detail and the mathematics of hydrostatic and how it fails in Doswell and Markowski's [paper][5] on buoyancy. But, with such limited model output, not sure that you're looking to get into all of that detail, as I don't believe you'll find any extra help going those avenues with the variables you have. With just slightly more information, most importantly temperature, you could use the [ideal gas law][7]: p = ρRT <sup>*[where R is the ideal gas constant of the gas under consideration and T is temperature in Kelvin]*</sup> This would allow you replace the unknown density, and you'd then end up with: **w = −ωRT/pg** Which you could then either further approximate R to be that for dry air = Rd = 287 J/Kkg, or even work up the adjustment your moisture content variable causes (though don't think doing so would offer much useful improvement as you've already got greater errors due to the failings of the hydrostatic approximation). Since you don't have temperature, it seems your only remaining option would be to plug in the density approximation for the level of interest from the approximated "Standard Atmosphere" [here][8] (use the table where ρ is in units of kg/m^3). It has been a long while since I've done this stuff, but I don't see any better options. Unless somehow there's a way to work from the geopotential, maybe apply something like mass continuity in pressure coordinates, and get to something more complex to return something more correct for w. But if there is, it outpaces me! **So, long story short, it appears that your best hope is w = −ωRT/pg, but it won't be 100% reliable, particularly in strong convection.** [1]: http://www.sjsu.edu/faculty/watkins/omega.htm [2]: https://www.e-education.psu.edu/meteo300/node/7 [3]: https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&cad=rja&uact=8&ved=0ahUKEwjJmqzPudDRAhUJLSYKHcarChQQFggdMAA&url=https%3A%2F%2Fwww.amazon.com%2FIntroduction-Dynamic-Meteorology-International-Geophysics%2Fdp%2F0123848660&usg=AFQjCNGdSbK_Pfo2P8HbJIyT5NckdVTUpg&sig2=7CCPxD8f00nU6vubKHTuJw [4]: https://books.google.com/books?id=-ePQ6x6VbjgC&pg=PA202&lpg=PA202&dq=estimating%20w%20from%20omega%20qg&source=bl&ots=l3lT-YIsiq&sig=aOb6ZXDWv7f9Vp_IGUgxtqYDgWM&hl=en&sa=X&ved=0ahUKEwjk3rnptdDRAhXLRiYKHTzRA1Q4ChDoAQgoMAI#v=onepage&q=estimating%20w%20from%20omega%20qg&f=false [5]: http://www.cimms.ou.edu/~doswell/relbuoy/relbuoy.html [6]: https://en.wikipedia.org/wiki/Reynolds_decomposition [7]: https://en.wikipedia.org/wiki/Ideal_gas_law [8]: http://www.engineeringtoolbox.com/standard-atmosphere-d_604.html

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\ begingroup美元你需要一个水平平衡条件计算“ω”。垂直balanace aka流体静力平衡无法奏效。我使用了路上ω计算理论ω。 \ endgroup美元
- - - - - -gansub
2017年1月20日在18:46
\ begingroup美元过一段时间,就像我说…你认为该模型需要一个平衡计算ω?他说他有ω。如果你说模型是使用,我可以看到真正的考虑到产量有限…但是我认为你可以从一个完整的原始方程模式得到ω压力坐标很好没有任何平衡的假设? \ endgroup美元
- - - - - -JeopardyTempest
2017年1月21日在0:49
\ begingroup美元取决于他是使用什么样的模型——中尺度或GCM。通常他们不包括平衡条件但这是什么诊断路上ω。带输出GCM和计算理论ω \ endgroup美元
- - - - - -gansub
2017年1月21日在2:56

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