>这意味着从赤道到北极的角度来看,这是顺时针旋转的部分你做错了。从赤道(地球上的任何其他的点),北极不旋转。旋转只出现在一个外部的参照系。,实际上是使用一个内部的参照系(像一个观察者在赤道)产生科里奥利力,并不是一个真正的力量,但只是从一个旋转的惯性参照系。从赤道,北极是定位,以及天球北极,这是解决由于北赤道地平线。但开始,太阳绕它从东到西,是逆时针* * * *。这是因为观察者向东移动。科里奥利更容易理解如果你想象地球表面上的任何点(或大气中)赤道以北的,必须完成一个环绕地球的小圆轴每24小时。因此,这些点正在向东以较慢的速度比在赤道。因此,如果你射弹,将超额向东速度相对于地面下它,所以它会向东去。 Which will apear like it is turning **rightwards**. If the projectile is flying south from the Equator, Eastwards will mean **leftwards**. This schematics from [Facts About All][1] will help in an example: [![enter image description here][2]][2] Let's imagine you are at at the monument "La Mitad del Mundo" right on the Equatorial line on Ecuador. And you shoot a projectile straight North to Raleigh, North Carolina, 3,960 km North of "La Mitad del Mundo". Let's say your canon shoots a frictionless projectile at speed of 1,000 km/h. Then the projectile had a Northwards speed of 1,000 km/h, and an Eastward speed of 1,666 km/h which is the speed the canon at Ecuador have in order to go around the earth center every 24 hours. Now, in 3.96 hours, the projectile would have reached the latitude of Raleigh, but in the same amount of time the eastward component of its speed took it 6,600 km to the East. However, the eastward velocity of Raleigh is only 1356 km/h That is because at latitude 35.7° the distance to the Earth rotation axis is only 5,179 km (in contrast with 6,378 km at the equator), therefore, the distance it have to travel around it every 24 hours is only 32,540 km (in contrast to 40,000) requiring a speed of just 1356 km/h. That means that, while the projectile wast traveling, Raleigh only moved 5,369 km eastwards, 1,231 km less than the projectile, with the consequence that the projectile ended up, 1,231 km to the East of Raleigh (The right as seen from "La Mitad del Mundo"), catastrophically missing the target, and falling in the Atlantic ocean somewhere north of Bermuda. This excess eastward velocity visualization of Coriolis, seemingly falls apart when considering a projectile shoot due East or West. But it would still be deflected to the right (in the northern hemisphere). An explanation in such case can be found in [this][3] answer, however that answer is not as clear as I would like, as it just ignores the vertical effect, also known as [Eötvös effect][4], which is important to make sense of the deflection of a projectile traveling East/West. In short, the increased/decreased velocity of a projectile moving East/West, increase/decrease the centrifugal force, so it moves away/towards from Earth's axis of rotation. This means "moves up" at the equator, and move south/north and up (in different proportions) north of the equator. The rightwards deflection is considered part of the Coriolis effect, while the upwards deflection is the Eötvös effect. [1]: http://factspage.blogspot.ca/2014/01/what-is-coriolis-effect.html [2]: https://i.stack.imgur.com/fQmut.png [3]: https://physics.stackexchange.com/questions/43124/is-there-an-intuitive-explanation-for-the-southward-force-caused-by-the-coriolis/52509#52509?newreg=d1833cf8d2ea4bbd80eb306f36b85bd9 [4]: https://en.wikipedia.org/wiki/E%C3%B6tv%C3%B6s_effect