如果你想知道什么是水的实际发射率(这是非常重要,甚至了解什么大小GHE !),你可以谷歌。遗憾的是你会得到各种各样的结果,所以,你没有得到任何更聪明。所以我不得不探讨的问题。我使用了从维基百科(菲涅耳方程)[2](“翻译”成Excel): [2]: https://en.wikipedia.org/wiki/Fresnel_equations Power_(强度)_reflection_and_transmission_coefficients ' ' ' Rs = ((B 1美元* COS (C5) - B美元2 * (1 - (B 1美元/ B美元$ 2 * SIN (C5)) ^ 2) ^ 0.5) / (B 1美元* COS (C5) + B美元2 * (1 - (B 1美元/ B美元$ 2 * SIN (C5)) ^ 2) ^ 0.5)) ^ 2卢比= ((B 1美元* (1 - (B 1美元/ B美元$ 2 * SIN (C5)) ^ 2) ^ 0.5 - B 2美元* COS (C5)) / (B 1美元* (1 - (B 1美元/ B美元$ 2 * SIN (C5)) ^ 2) ^ 0.5 + B 2美元* COS (C5))) ^ 2 ' ' '与' ' ' B 1美元= N1 B 2 =美元N2 C5、C6 . .=各自的角度/ 180 *π()”“还有(这个非常有用的网站)[1],给你水的光学性质的信息。[1]:https://refractiveindex.info/?黑尔货架=主要著作= H2O&page =现在如果我输入一个波长的“1”我得到一个折射率(n = 1.327。在我计算我用这个与N1 N2 = 1.327 = 1(空气)。如果你向下滚动页面有一个部分叫“反射计算器”给你计算结果的光反射表面的水,在给定波长对于任何给定的角。 The great thing is, that when I compare these results (those in my excel sheet and those on this site) they perfectly match, for every angle, for at least 6 digits. Naturally that gave me the confidence that I did everything right. Just recently I stumbled over a problem. For instance I can enter a wavelength of 16.039, which incidentally also has a refractive index of n = 1.327. In my excel sheet the outcome will be the same, as the refractive index is the only relevant input. But now the "Reflection calculator" gives me a very different result which does not match my excel results. So the logic suggests the formula they use there is after all different the formula I described above and includes another parameter. I assume that parameter might be the "extinction coefficient" k, which is very small at a wavelength of 1, but quite substantial at 16.039. Do you have any idea what the formula used on this site might actually look like?